document.write( "Question 1130970: Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 21 cards, and 4 are selected without replacement for functional testing.\r
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document.write( "(Please enter your answers as fractions in lowest terms or as decimals rounded to four decimal places. Thank you!)\r
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document.write( "a. If 15 cards are defective, what is the probability that at least one defective card is in the sample?\r
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document.write( "b. If 14 cards are defective, what is the probability that at least one defective card is in the sample? \n" );
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Algebra.Com's Answer #749340 by Boreal(15235) You can put this solution on YOUR website! Find probability no defective cards are and subtract from one. \n" ); document.write( "(6/21)(5/20)(4/19)(3/18)=(2/7)(1/4)(4/19)(1/6)=2/798=1/399 \n" ); document.write( "398/399 is the probability at least one card is defective.\r \n" ); document.write( "\n" ); document.write( "(7/21)(6/20)(5/19)(4/18)=(1/3)(3/10)(5/19)(2/9)=1/171 \n" ); document.write( "so the probability is 1-1/171 or 170/171\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |