document.write( "Question 1132329:
\n" ); document.write( "Points A, B, Q, D, and C lie on the circle as shown and the measures of arcs BQ and QD are 42° and 38° respectively. What is the sum of the angles P and Q? \r
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\n" ); document.write( "\n" ); document.write( "https://associations.missouristate.edu/assets/Math/Practice_Probs_Sept_2013_-_Solutions.pdf\r
\n" ); document.write( "\n" ); document.write( "Question 4 - Can someone explain this?/\r
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Algebra.Com's Answer #749336 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
It is a property of circles and secants that if two secants intersect outside of the circle (PB and PD) the angle formed (angle P) will be 1/2 the difference of the two intercepted arcs: angle P = 1/2(arc_BD - arc_AC)
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\n" ); document.write( "\n" ); document.write( "Angle Q is 1/2 arc_AC (inscribed angles are 1/2 their central angle)
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\n" ); document.write( "\n" ); document.write( "angle P + angle Q = (1/2)(arc_AC) + (1/2)(arc_BD - arc_AC) = (1/2)(arc_BD) = (1/2)(80) = 40 degrees
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\n" ); document.write( "\n" ); document.write( "Remember, the angle of an arc is the central angle that it sweeps, none of which are drawn on the Question 4 diagram
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