document.write( "Question 1132289: 2x+y-2z=10;3x+2y+2z=1; 5x+4y+3z=4
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Algebra.Com's Answer #749308 by MathTherapy(10556)\"\" \"About 
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\n" ); document.write( "2x+y-2z=10;3x+2y+2z=1; 5x+4y+3z=4
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2x + y - 2z = 10 -------- eq (i)
\n" ); document.write( "3x + 2y + 2z = 1 -------- eq (ii)
\n" ); document.write( "5x + 4y + 3z = 4 -------- eq (iii)
\n" ); document.write( "6x + 4y + 4z = 2 -------- Multiplying eq (ii) by 2 ----- eq (iv)
\n" ); document.write( "x + z = - 2 ------ Subtracting eq (iii) from (iv) ------ eq (v)
\n" ); document.write( "- 4x - 2y + 4z = - 20 --- Multiplying eq (i) by - 2 ---- eq (vi)
\n" ); document.write( "- x + 6z = - 19 --------- Adding eqs (vi) & (ii) ------- eq (vii)
\n" ); document.write( "7z = - 21 ---------- Adding eqs (vii) & (v)
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\n" ); document.write( "\n" ); document.write( "x - 3 = - 2 -------- Substituting - 3 for z in eq (v)
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\n" ); document.write( "\n" ); document.write( "2(1) + y - 2(- 3) = 10 ------- Substituting 1 for x, and - 3 for z in eq (i)
\n" ); document.write( "2 + y + 6 = 10
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