document.write( "Question 1132285: 5 of 10 employees of a corporation are men . Suppose that 4 employees are selected at random as delegates for a conference.how many selections will contain : a) exacrly 3 men ? B) at least 3 men ? C) what is the probability that a random selection will contain exactly 3 men ? \n" ); document.write( "
Algebra.Com's Answer #749278 by ikleyn(52858)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "a)   exactly 3 men ?\r
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document.write( "    (select 3 of 5 men) * (select 1 of 5 women) = \"C%5B5%5D%5E3\".\"C%5B5%5D%5E1\" = \"%285%2A4%29%2F%281%2A2%29\".\"5\" = 10*5 = 50 different selections.\r\n" );
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\n" ); document.write( "\n" ); document.write( "b)   at least 3 men ?\r
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document.write( "    (select 3 of 5 men) * (select 1 of 5 women) + (select 4 of 5 men) = \"C%5B5%5D%5E3\".\"C%5B5%5D%5E1\" + \"C%5B5%5D%5E4\" = 50 + 5 = 55 different selections.\r\n" );
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\n" ); document.write( "\n" ); document.write( "c)   what is the probability that a random selection will contain exactly 3 men ?\r
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document.write( "    P = \"%28C%5B5%5D%5E3%2AC%5B5%5D%5E1%29%2FC%5B10%5D%5E4\" = \"%28%2810%2A5%29%29%2F%28%28%2810%2A9%2A8%2A7%29%2F%281%2A2%2A3%2A4%29%29%29\" = \"50%2F210\" = \"5%2F21\" = 0.2381 = 23.81% (approximately).\r\n" );
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