document.write( "Question 102975: What is the P-value for the testing of the following hypothesis for someone who gets 25 right out of 100? 30 right? 35 Right? 50 right?\r
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document.write( "The null hypothesis is p=.2 that a person is guessing in an ESP experiment where one person randomly draws one of 5 cards and the \"reciever\" person tries to determine which card it is. The alternative hypothesis is p>.2 is to show support that the person is doing better than guessing. \n" );
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Algebra.Com's Answer #74923 by stanbon(75887) ![]() You can put this solution on YOUR website! What is the P-value for the testing of the following hypothesis for someone who gets 25 right out of 100? 30 right? 35 Right? 50 right? \n" ); document.write( "The null hypothesis is p=.2 that a person is guessing in an ESP experiment where one person randomly draws one of 5 cards and the \"reciever\" person tries to determine which card it is. The alternative hypothesis is p>.2 is to show support that the person is doing better than guessing. \n" ); document.write( "------------------------ \n" ); document.write( "Ho: p=0.2 \n" ); document.write( "Ha: p>0.2 \n" ); document.write( "-------------- \n" ); document.write( "If p-hat = 25/100 = 0.25 \n" ); document.write( "then z(0.25)= (0.25-0.20)/[sqrt[(0.2*0.8/25)] = 0.05/0.04/5 = 5*0.05/0.04 \n" ); document.write( "= 0.625 \n" ); document.write( "The the p-value associated with this z value is 0.266 \n" ); document.write( "-------------- \n" ); document.write( "Do the same for p-hat = 30/100, then p-hat=35/100, the p-hat=50/100 \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |