document.write( "Question 1132219: Jamie is 5 years older than her brother. Five years ago she was 2 times older than her brother. How old are they?
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Algebra.Com's Answer #749181 by Alan3354(69443)\"\" \"About 
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Jamie is 5 years older than her brother. Five years ago she was 2 times older than her brother. How old are they?
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\n" ); document.write( "Five years ago she was 2 times older than her brother.
\n" ); document.write( "1 time older = 2 times as old.
\n" ); document.write( "2 times older = 3 times as old.
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\n" ); document.write( "The difference is always 5 years.
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\n" ); document.write( "5 years ago:
\n" ); document.write( "J = B + 5
\n" ); document.write( "J = 3B
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\n" ); document.write( "Sub for J in the 1st eqn
\n" ); document.write( "3B = B + 5
\n" ); document.write( "2B = 5
\n" ); document.write( "B = 2.5
\n" ); document.write( "J = 7.5
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\n" ); document.write( "Add 5
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\n" ); document.write( "B = 7.5
\n" ); document.write( "J = 12.5
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\n" ); document.write( "\"2 times older\" shows the author of the problem should find other work.
\n" ); document.write( "But, at least it's not \"2 times younger.\"
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