document.write( "Question 1132202: Four members of one family have a combined age of 135 years.\r
\n" ); document.write( "\n" ); document.write( "Jeff is twice as old as his daughter Ann, while Trudy is 5 years younger than her husband, Jeff.\r
\n" ); document.write( "\n" ); document.write( "Harry is a third of his mother Trudy's age.\r
\n" ); document.write( "\n" ); document.write( "How old are each of the four members of this family? \n" ); document.write( "
Algebra.Com's Answer #749162 by MathTherapy(10552)\"\" \"About 
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Four members of one family have a combined age of 135 years.\r
\n" ); document.write( "\n" ); document.write( "Jeff is twice as old as his daughter Ann, while Trudy is 5 years younger than her husband, Jeff.\r
\n" ); document.write( "\n" ); document.write( "Harry is a third of his mother Trudy's age.\r
\n" ); document.write( "\n" ); document.write( "How old are each of the four members of this family?
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Let Ann's age be A
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document.write( "Then Jeff's is 2A, Trudy's is 2A - 5, and Harry's is \"matrix%281%2C3%2C+%281%2F3%29%282A+-+5%29%2C+or%2C+%282A+-+5%29%2F3%29\"
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document.write( "We then get: \"matrix%281%2C3%2C+A+%2B+2A+%2B+2A+-+5+%2B+%282A+-+5%29%2F3%2C+%22=%22%2C+135%29\"
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document.write( "\"matrix%281%2C3%2C+5A+%2B+%282A+-+5%29%2F3%2C+%22=%22%2C+140%29\"
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document.write( "15A + 2A - 5 = 420 -------- Multiplying by LCD, 3
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document.write( "17A = 425
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document.write( "We then get:  \n" );
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