document.write( "Question 1132177: A man born in the first half of the 19th century was x years old in the year x2. He was born in: (A) 1849 (B) 1806 (C) 1812 (D) 1825 \n" ); document.write( "
Algebra.Com's Answer #749118 by ikleyn(52794)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The 19-th century is the time period from 1801 to 1900, inclusively.\r\n" );
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document.write( "\"sqrt%281801%29\" = 42.44 (approximately);\r\n" );
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document.write( "\"sqrt%281900%29\" = 43.59 (approximately).\r\n" );
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document.write( "Therefore, the only positive integer number x, whose square  \"x%5E2\" lies between 1801 and 1900 is 43.\r\n" );
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document.write( "\"43%5E2\" = 1849.\r\n" );
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document.write( "So, the problem says that the man was 43 years old in the year 1849.\r\n" );
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document.write( "Hence, he was born in the year 1849 - 43 = 1806.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "This problem is very well known,  and it was solved at this forum  MANY  TIMES  (about  10  times).\r
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\n" ); document.write( "\n" ); document.write( "See,  for example,  this link\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.1126192.html\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.1126192.html\r
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\n" ); document.write( "\n" ); document.write( "as well as many other links \r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.493026.html\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.829890.html\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.16844.html\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.982465.html\r
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