document.write( "Question 1131566: . A population has variance σ^2=100. A random sample of 25 from this population had a mean equal
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document.write( " 17 and an estimated standard deviation equal 16. Can we conclude that the population mean is less
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document.write( " than 25? Let α=5%. Assume x is normally distributed. Hint, find σ_x .
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Algebra.Com's Answer #749092 by Theo(13342)![]() ![]() You can put this solution on YOUR website! population variance is 100 \n" ); document.write( "population standard deviation is sqrt(100) = 10 \n" ); document.write( "sample size is 25. \n" ); document.write( "sample mean is 17 \n" ); document.write( "sample standard deviation is 16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you know the population standard deviation, then you use that. \n" ); document.write( "otherwise you use the sample standard deviation and then the t-score rather than the z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 95% confidence level, the z-score will be plus or minus 1.96.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m) / s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard error = population stnadard deviation / sqrt (sample size).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that becomes s - 10 / sqrt(25) = 10 / 5 = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the high side for z, the formula becomes 1.96 = (x-17) / 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 2 * 1.96 + 17 = 3.92 + 17 = 20.92\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the low side for z, the formula becomes -1.96 = (1-17) / 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = -2 * 1.96 + 17 = 13.08.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 95% confident level, the true population mean is expected to be between 13.08 and 20.92.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on this, you can conclude that the true population mean is less than 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's my take.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's some info on when to use t-score versus z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.statisticshowto.datasciencecentral.com/probability-and-statistics/hypothesis-testing/t-score-vs-z-score/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |