document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103025>Question 103025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is one more year than 4 times the age of her daughter. In 4 years, she will be 3 times as old as her daughter will be then. What are their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74906 by </B><A HREF=/tutors/aboutme.mpl?userid=rossiv53><B>rossiv53(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rossiv53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = daughter's age and (4x+1) = the mother's age.  In 4 years their ages will be (x+4) = daughter's age and (4x+1)+4 = the mother's age.  Now in 4 years the mother will be 3 times as old.  This means the equation is 3 times the daughter's age in 4 years = to the mother's age in 4 years.\r<BR>\n" );
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document.write( "3(x+4) = (4x+1)+4)<BR>\n" );
document.write( "3x+12 = 4x+5<BR>\n" );
document.write( "3x+12-12 = 4x+5-12<BR>\n" );
document.write( "3x = 4x-7<BR>\n" );
document.write( "3x-4x = -7<BR>\n" );
document.write( "-x = -7<BR>\n" );
document.write( "x = 7\r<BR>\n" );
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document.write( "So, daughter's age now is 7 and since mother's age is 4x+1, her age is 29.<BR>\n" );
document.write( "Good luck! </SPAN>\n" );
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