document.write( "Question 103029: if i have a problem like this \r
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document.write( "-3(x+5)=3(x-1) how would i slove it and check it the check part is what i dont understand how to do it \n" );
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Algebra.Com's Answer #74904 by doukungfoo(195)![]() ![]() You can put this solution on YOUR website! solving for x \n" ); document.write( "-3(x+5)=3(x-1) \n" ); document.write( "first multiply -3 across (x+5) \n" ); document.write( "-3x - 15 = 3(x-1) \n" ); document.write( "next multiply 3 across (x-1) \n" ); document.write( "-3x - 15 = 3x - 3 \n" ); document.write( "now move all terms with x to the left side \n" ); document.write( "-3x - 3x -15 = -3 \n" ); document.write( "Then move all terms without x to the right side \n" ); document.write( "-3x - 3x = -3 + 15 \n" ); document.write( "combine like terms \n" ); document.write( "-6x = 12 \n" ); document.write( "finally solve for x by dividing both sides by -6 \n" ); document.write( "-6x/-6 = 12/-6 \n" ); document.write( "x = -2 \n" ); document.write( "Ok so we have solved for x and found that x = -2 \n" ); document.write( "To check the answer just take the orginal equation \n" ); document.write( "-3(x+5)=3(x-1) \n" ); document.write( "and replace the x with -2 \n" ); document.write( "-3(-2+5)=3(-2-1) \n" ); document.write( "now just do the math \n" ); document.write( "-3(3) = 3(-3) \n" ); document.write( "-9 = -9 \n" ); document.write( "we end up with a true state \n" ); document.write( "so we know that -2 is the correct answer. \n" ); document.write( " |