document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132117>Question 1132117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Solution A contains 45% hydrogen and Solution B contains 69% hydrogen. How much of each solution should be mixed in order to create 150 liters of a solution that contains 61% hydrogen?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #749033 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=749033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way: there is a 24% difference absolutely between the two solutions.  The 61% is 2/3 of the way to 69%, so it should be 2/3 of the amount.\r<BR>\n" );
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document.write( "x=45%<BR>\n" );
document.write( "150-x=69%<BR>\n" );
document.write( ".45x+(150-x)*.69=150*0.61=91.5<BR>\n" );
document.write( ".45x+103.5-.69x=91.5<BR>\n" );
document.write( "-.24x=-12<BR>\n" );
document.write( "x=50 liters of 45%<BR>\n" );
document.write( "150-x=100 liters of 69%<BR>\n" );
document.write( "(100/150) is 2/3. </SPAN>\n" );
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