document.write( "Question 1132114: a woman has 25 years old when her daughter was born. the mother's present age is 10 years more than 4 times her daughter's present age. find the present age of each. (use only one variable) (thanks in advance) \n" ); document.write( "

Algebra.Com's Answer #749016 by Theo(13342) $\"\"$ $\"About$

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let x = the daughter's current age.
\n" ); document.write( "then x + 25 = the mother's current age, because the mother was 25 when the daughter was born.
\n" ); document.write( "the mother's current age is 10 more than 4 times the daughter's age.
\n" ); document.write( "formula for that is x + 25 = 10 + 4 * x.
\n" ); document.write( "subtract x from both sides of that equation and subtract 10 from both sides of that equation to get x + 25 - x - 10 = 10 + 4 * x - x - 10
\n" ); document.write( "combine like terms to get 15 = 3 * x
\n" ); document.write( "solve for x to get x = 15 / 3 = 5
\n" ); document.write( "the daughter's current age is 5.
\n" ); document.write( "the mother's current age is 5 + 25 = 30
\n" ); document.write( "the mother's current age of 30 is equal to 10 + 4 times the daugher's current age = 10 + 4 * 5 = 30.
\n" ); document.write( "solution checks out.
\n" ); document.write( "solution is that the daughter's current age is 5 and the mother's current age is 30.\r
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