document.write( "Question 1132112: the sum of the digits of a two digit number is 11. the new number obtained when the digits are reversed is 7 more than twice the original number. find the original number.(use only one variable and this is a digit number problem) (thanks in advance) \n" ); document.write( "
Algebra.Com's Answer #749014 by ikleyn(52915) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let the ones digit of the number is A; then the tens digit is (11-A).\r\n" ); document.write( "\r\n" ); document.write( "Hence, the digit itself is 10*(11-A) + A.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the digits are reversed in the number, the new number is 10A +(11-A).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The new number and the original number are related each to other by this equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "10A + (11-A) = 2*(10*(11-A) + A) + 7.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "We just completed the setup.\r\n" ); document.write( "We have now one equation for single unknown A.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve for A:\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "10A + 11 - A = 2*(110 - 10A + A) + 7\r\n" ); document.write( "\r\n" ); document.write( "9A + 11 = 220 - 18A + 7\r\n" ); document.write( "\r\n" ); document.write( "9A + 18A = 227 - 11\r\n" ); document.write( "\r\n" ); document.write( "27A = 216\r\n" ); document.write( "\r\n" ); document.write( "A =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check it on your own that the solution and the answer are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good problem. Hope everything is clear to you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |