document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131141>Question 1131141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a survey by the Administrative Management Society, one-half of U.S. companies give employees 4 weeks of vacation after they have been with the company for 15 years. Find the probability that among 6 companies surveyed at random, the number that give employees 4 weeks of vacation after 15 years of employment is (a) anywhere from 2 to 5; (b) fewer than 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #749011 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=749011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability for 0 would be .5^6=0.015625<BR>\n" );
document.write( "for 1 is 6C1 is 6*015625=0.09375<BR>\n" );
document.write( "for 2 is 15*0.015625=0.234<BR>\n" );
document.write( "for 3 is 20*0.015625=0.3125<BR>\n" );
document.write( "for 4 is 0.234<BR>\n" );
document.write( "for 5 it is 0.09375<BR>\n" );
document.write( "for 6 it is 0.015625\r<BR>\n" );
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document.write( "From 2 to 5 it is 1- P(0, 1, 6) or 1-0.125=0.875\r<BR>\n" );
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document.write( "fewer than 3 is P(0, 1, 2)=0.343 </SPAN>\n" );
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