document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15047>Question 15047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello<BR>\n" );
document.write( "I am trying to go back to school I have never liked math. Now that I need to take a test to enter college I am confused I have the THEA guide book. But they really don't explain to well the problems. Anyways I am trying to figure this out 2x+3y=6 I need to graph but first I need to solve for x and then solve for Y. Please I hope you can help me!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7490 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm not familiar with the THEA guide book, but when you are graphing an equation like 2x + 3y = 6, I can't imagine why you would want to solve for x.  Solving for y is a nice idea, but I don't think that is the easiest way to graph this equation.\r<BR>\n" );
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document.write( "Nevertheless, solve for y by adding -2x from both sides:<BR>\n" );
document.write( "2x + 3y = 6<BR>\n" );
document.write( "2x-2x + 3y = -2x + 6<BR>\n" );
document.write( "3y = -2x + 6\r<BR>\n" );
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document.write( "Next, divide both sides by 3 in order to solve for y.<BR>\n" );
document.write( "3y= -2x + 6<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283y%29%2F3+=+%28-2x%29%2F3+%2B+6%2F3 ALIGN=MIDDLE  ALT=\"%283y%29%2F3+=+%28-2x%29%2F3+%2B+6%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2x%2F3+%2B+2 ALIGN=MIDDLE  ALT=\"y+=+-2x%2F3+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "What this means is the the y intercept is 2, and the slope (steepness!) of the line is -2/3.\r<BR>\n" );
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document.write( "Start with an xy graph, and go up two units on the y-axis and put a point.  Next, with your pencil on this point on the y axis, measure off the slope which is a rise of -2 followed by a run of 3.  This means from the point you made at y=2 on the y-axis, count DOWN 2 units, and go RIGHT 3 units, and put another point.  Then connect the points with a line, and extend the line in both directions. The result should look like this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph+%28300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%28-2%2F3%29%2Ax+%2B+2%29++ ALIGN=MIDDLE  ALT=\"graph+%28300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%28-2%2F3%29%2Ax+%2B+2%29++\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC<BR>\n" );
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