document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132102>Question 1132102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If ax³ + bx² + x - a = 0 is exactly divisible by (x+3) and by (2x-1), find a and b.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748996 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "From the given information, we know that two of the roots are -3 and 1/2.<br><BR>\n" );
document.write( "Vieta's Theorem tells us the product of the three roots of a cubic polynomial is (opposite of constant term) divided by (leading coefficient): a/a = 1.<br><BR>\n" );
document.write( "Therefore, the third root is -2/3.<br><BR>\n" );
document.write( "So the polynomial is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B3%29%282x-1%29%283x%2B2%29+=+6x%5E3%2B19x%5E2%2Bx-6 ALIGN=MIDDLE  ALT=\"%28x%2B3%29%282x-1%29%283x%2B2%29+=+6x%5E3%2B19x%5E2%2Bx-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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