document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132102>Question 1132102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If ax³ + bx² + x - a = 0 is exactly divisible by (x+3) and by (2x-1), find a and b.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748993 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> that means that 2 roots are -3 and +1/2<BR>\n" );
document.write( "-27a+9b-3-a=0<BR>\n" );
document.write( "-28a+9b=3<BR>\n" );
document.write( "1/8 a+1/4b+1/2-a=0<BR>\n" );
document.write( "-7a+2b=-4\r<BR>\n" );
document.write( "\n" );
document.write( "28a-8b=16<BR>\n" );
document.write( "-28a+9b=3<BR>\n" );
document.write( "b=19<BR>\n" );
document.write( "a=6<BR>\n" );
document.write( "6x^3+19x^2+x-6=0<BR>\n" );
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