document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132103>Question 1132103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The roots of the equation x² + 2px + q = 0 differ by 2. Show that<BR>\n" );
document.write( "p² = 1 + q </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748992 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> roots are (1/2)(-2+/- sqrt (4p^2-4q))<BR>\n" );
document.write( "sqrt(4p^2-4q)=2*sqrt(p^2-q).  2s cancel<BR>\n" );
document.write( "roots are -1+sqrt(p^2-q) and -1- sqrt(p^2-q)<BR>\n" );
document.write( "the difference is 2sqrt(p^2-q) and that equals 2<BR>\n" );
document.write( "so sqrt(p^2-q)=1<BR>\n" );
document.write( "p^2-q=1, squaring both sides<BR>\n" );
document.write( "p^2=1+q \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );