document.write( "Question 1132096: Given that 4^-n = 32.
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document.write( "Find the value of n \n" );
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Algebra.Com's Answer #748983 by Alan3354(69443) You can put this solution on YOUR website! Given that 4^-n = 32. \n" ); document.write( "Find the value of n \n" ); document.write( "========= \n" ); document.write( "Find the log of each side. \n" ); document.write( " \n" ); document.write( "-n*log(4) = log(32) \n" ); document.write( "n = -log(32)/log(4) \n" ); document.write( "n = -2.5 \n" ); document.write( "===================== \n" ); document.write( "Edwin's approach is simpler, but could not be used if the problem were: \n" ); document.write( "Given that 4^-n = 33. \n" ); document.write( "Find the value of n \n" ); document.write( " |