document.write( "Question 1132035: Land in the shape of an isosceles triangle has a base of 130 m. An altitude from one of the legs of the triangle is 120 m. What is the area of the property?
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\n" ); document.write( "Can someone please solve this without using trignometry.
\n" ); document.write( "a) 3000
\n" ); document.write( "b) 9840
\n" ); document.write( "c) 9512
\n" ); document.write( "d) 10 140
\n" ); document.write( "e) 10 200
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Algebra.Com's Answer #748874 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Let AB be the base, with AD the altitude to side BC; AC = BC = x.

\n" ); document.write( "ADB is a right triangle with one leg AD = 120 and hypotenuse AB = 130; that makes leg BD 50.

\n" ); document.write( "Now triangle ACD is also a right triangle; the hypotenuse AC is x, leg AD is 120, and leg CD is x-50. Then

\n" ); document.write( "\"x%5E2+=+120%5E2+%2B+%28x-50%29%5E2\"
\n" ); document.write( "\"x%5E2+=+14400+%2B+x%5E2-100x%2B2500\"
\n" ); document.write( "\"0+=+16900-100x\"
\n" ); document.write( "\"100x+=+16900\"
\n" ); document.write( "\"x+=+169\"

\n" ); document.write( "We can find the area of the triangle using BC as the base, since AD is the altitude to that base:

\n" ); document.write( "\"A+=+%281%2F2%29%28169%29%28120%29+=+169%2A60+=+10140\"

\n" ); document.write( "Answer d.
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