document.write( "Question 1132035: Land in the shape of an isosceles triangle has a base of 130 m. An altitude from one of the legs of the triangle is 120 m. What is the area of the property?
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document.write( "Can someone please solve this without using trignometry.
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document.write( "a) 3000
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document.write( "b) 9840
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document.write( "c) 9512
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document.write( "d) 10 140
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document.write( "e) 10 200 \n" );
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Algebra.Com's Answer #748874 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "Let AB be the base, with AD the altitude to side BC; AC = BC = x. \n" ); document.write( "ADB is a right triangle with one leg AD = 120 and hypotenuse AB = 130; that makes leg BD 50. \n" ); document.write( "Now triangle ACD is also a right triangle; the hypotenuse AC is x, leg AD is 120, and leg CD is x-50. Then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We can find the area of the triangle using BC as the base, since AD is the altitude to that base: \n" ); document.write( " \n" ); document.write( "Answer d. \n" ); document.write( " |