document.write( "Question 102961: Suuppose that Wendy rides her bicycle 30 miles in the same time that it takes kim to ride her bicycle 20 miles. IF wendy rides 5 miles per hour faster than kim, find the rate of each. \n" ); document.write( "
Algebra.Com's Answer #74887 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose that Wendy rides her bicycle 30 miles in the same time that it takes Kim to ride her bicycle 20 miles. IF Wendy rides 5 miles per hour faster than Kim, find the rate of each.
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\n" ); document.write( "Let s = K's speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = W's speed
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\n" ); document.write( "Since they tell us the the two times are the same, we can make a simple time
\n" ); document.write( "equation from this fact: Time = Distance/Speed
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\n" ); document.write( "K's time = W's time
\n" ); document.write( "\"20%2Fs\" = \"30%2F%28%28s%2B5%29%29\"
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\n" ); document.write( "Cross multiply
\n" ); document.write( "30s = 20(s+5)
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\n" ); document.write( "30s = 20s + 100
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\n" ); document.write( "30s - 20s = 100
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\n" ); document.write( "10s = 100
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\n" ); document.write( "s = 10 mph is K's speed and 15 mph is W's speed
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\n" ); document.write( "Check solution by find the time of each:
\n" ); document.write( "20/10 = 30/15
\n" ); document.write( " 2 = 2
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