document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1132020>Question 1132020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On weekdays, a movie theater charges different rates for adults and children. If 3 adults and 2 children go for a movie on a weekday, the total cost of the tickets is $31. If 2 adults and 3 children go on a weekday, the total cost of the tickets is $29. If a group of adults and 6 children go to the movie theater on a weekday and pay $58 for tickets, how many adults are in this group? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748829 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3A+2C=31<BR>\n" );
document.write( "2A+3C=29<BR>\n" );
document.write( "xA+6C=58 from the second row this would be 4A, doubling everything  ANSWER\r<BR>\n" );
document.write( "\n" );
document.write( "-6A-4C=-62<BR>\n" );
document.write( "6A+9C=87<BR>\n" );
document.write( "5C=25<BR>\n" );
document.write( "C=$5<BR>\n" );
document.write( "3A=21 <BR>\n" );
document.write( "A=$7<BR>\n" );
document.write( "check the xA+6C and when A=$4 and C=$5, it is $58<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );