document.write( "Question 1131967: 1: true or false
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document.write( "1000........................................998
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document.write( "(Sigma)7 (3/4)^n. = 63/16 (sigma)(3/4)^n
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document.write( "N=2.........................................n=0 \n" );
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Algebra.Com's Answer #748793 by greenestamps(13215) You can put this solution on YOUR website! \n" ); document.write( "The other tutor appears to have overlooked part of the statement of the problem. \n" ); document.write( "The two sums are the same, because each term of one sequence is the same as the corresponding term of the other sequence. \n" ); document.write( "First terms: \n" ); document.write( "first sequence: 7(3/4)^2 = 7(9/16) = 63/16 \n" ); document.write( "second sequence: (63/16)(3/4)^0 = 63/16 \n" ); document.write( "Second terms: \n" ); document.write( "first sequence: 7(3/4)^3 = 7(27/64) = 189/64 \n" ); document.write( "second sequence: (63/16)(3/4)^1 = 189/64 \n" ); document.write( "etc., etc. \n" ); document.write( "Formally.... \r\n" ); document.write( "\r\n" ); document.write( " 1000 \r\n" ); document.write( " (sigma) 7(3/4)^n =\r\n" ); document.write( " n=2\r\n" ); document.write( "\r\n" ); document.write( " 1000\r\n" ); document.write( " 7*(sigma) (3/4)^n = [move the constant 7 outside the summation symbol]\r\n" ); document.write( " n=2\r\n" ); document.write( "\r\n" ); document.write( " 1000\r\n" ); document.write( " (7(3/4)^2)*(sigma) (3/4)^(n-2) = [move 2 powers of (3/4) outside the summation symbol]\r\n" ); document.write( " n=2\r\n" ); document.write( "\r\n" ); document.write( " 998\r\n" ); document.write( " (63/16)*(sigma) (3/4)^n [redefine the index]\r\n" ); document.write( " n=0\n" ); document.write( " |