document.write( "Question 1131967: 1: true or false
\n" ); document.write( "1000........................................998
\n" ); document.write( "(Sigma)7 (3/4)^n. = 63/16 (sigma)(3/4)^n
\n" ); document.write( "N=2.........................................n=0
\n" ); document.write( "

Algebra.Com's Answer #748793 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "The other tutor appears to have overlooked part of the statement of the problem.

\n" ); document.write( "The two sums are the same, because each term of one sequence is the same as the corresponding term of the other sequence.

\n" ); document.write( "First terms:
\n" ); document.write( "first sequence: 7(3/4)^2 = 7(9/16) = 63/16
\n" ); document.write( "second sequence: (63/16)(3/4)^0 = 63/16
\n" ); document.write( "Second terms:
\n" ); document.write( "first sequence: 7(3/4)^3 = 7(27/64) = 189/64
\n" ); document.write( "second sequence: (63/16)(3/4)^1 = 189/64
\n" ); document.write( "etc., etc.

\n" ); document.write( "Formally....
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document.write( "   1000 \r\n" );
document.write( "  (sigma) 7(3/4)^n  =\r\n" );
document.write( "   n=2\r\n" );
document.write( "\r\n" );
document.write( "      1000\r\n" );
document.write( "   7*(sigma) (3/4)^n  =    [move the constant 7 outside the summation symbol]\r\n" );
document.write( "      n=2\r\n" );
document.write( "\r\n" );
document.write( "               1000\r\n" );
document.write( "   (7(3/4)^2)*(sigma) (3/4)^(n-2)  =    [move 2 powers of (3/4) outside the summation symbol]\r\n" );
document.write( "               n=2\r\n" );
document.write( "\r\n" );
document.write( "            998\r\n" );
document.write( "   (63/16)*(sigma) (3/4)^n    [redefine the index]\r\n" );
document.write( "            n=0
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