document.write( "Question 1132002: Please help me understand to solve these 3 problems (Algebra 2 factor grouping)
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Algebra.Com's Answer #748783 by ikleyn(52782) $\"\"$ $\"About$

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document.write( "1)  3x^3 - 12x^2 - 2x + 8 = \r\n" );
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document.write( "        Apply grouping.   Look: there are coefficients (3,-12) at x^3 and x^2    -  and  (-2,8)  at x  and the constant term.\r\n" );
document.write( "        It gives you an idea how to group:\r\n" );
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document.write( "    3x^3 - 12x^2 - 2x + 8 = (3x^3 - 12x^2) - (2x -8) = 3x^2*(x-4) - 2*(x-4)\r\n" );
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document.write( "        Now use that (x-4) is the common factor\r\n" );
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document.write( "    = (x-4)*(3x^2 - 2).\r\n" );
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document.write( "    Thus this factoring is COMPLETED over the polynomials with integer coefficients.\r\n" );
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document.write( "2)  4x^4  - 16x^2 - 9x^2 + 36\r\n" );
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document.write( "        THE SAME IDEA WORKS again:\r\n" );
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document.write( "    4x^4  - 16x^2 - 9x^2 + 36 = (4x^4  - 16x^2) - (9x^2 - 36) = 4x^2*(x^2-4) - 9*(x^2-4) = (x^2-4)*(4x^2-9) = (x-2)*(x+2)*(2x-3)*(2x+3).\r\n" );
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\n" ); document.write( "\n" ); document.write( "Let me leave the \" #3 \" for you to complete it on your own - use THE SAME IDEAS !\r
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\n" ); document.write( "\n" ); document.write( "Is everything clear to you ?\r
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\n" ); document.write( "\n" ); document.write( "If you still have questions, let me know.\r
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