document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131992>Question 1131992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help with this word problem: Gary sold tickets to the school football game. He sold $1240 worth of tickets. He sold 10 more adult tickets than children tickets and 4 times as many senior tickets than children tickets. If children tickets are $4, senior tickets are $6, and adult tickets are $10, how many children tickets did Gary sell? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748768 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A= adult tickets, C=children tickets, S=senior tickets<BR>\n" );
document.write( "A-10=C; C+10=A<BR>\n" );
document.write( "4C=S<BR>\n" );
document.write( "4C+6S+10A=1240, but S=4C and C=A-10<BR>\n" );
document.write( "4C+24C+10C+100=1240<BR>\n" );
document.write( "38C=1140<BR>\n" );
document.write( "C=30 children tickets and $120<BR>\n" );
document.write( "A=C+10=40 adult tickets and $400<BR>\n" );
document.write( "4C=S=120 senior tickets and $720<BR>\n" );
document.write( "adds to $1240. </SPAN>\n" );
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