document.write( "Question 1131947: Need help with this problem
\n" ); document.write( "Find the z-score for the standard normal
\n" ); document.write( "distribution where:
\n" ); document.write( "P(-a < z < 0) = 0.1844
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Algebra.Com's Answer #748696 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We know that \"P%28z+%3C+0%29+=+0.5\", so \"P%28z%3C-a%29+=+0.50+-+0.1844+=+0.3156\" \r
\n" ); document.write( "\n" ); document.write( "Using a Standard Normal table ... \r
\n" ); document.write( "\n" ); document.write( "\"P%28z%3C-a%29+=+0.3156%7B%7B%7B+has+%7B%7B%7Ba+=+0.48+\"\r
\n" ); document.write( "\n" ); document.write( "\"P%28-0.48%3Cz%3C0%29+=+0.1844+\"\r
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\n" ); document.write( "\n" ); document.write( "or this way:\r
\n" ); document.write( "\n" ); document.write( "\"P%28-a%3Cz%3C0%29+=+0.1844+\"
\n" ); document.write( "\"P%28+0+%3C+z+%3C+a%29+=+0.1844\" (because of symmetry)
\n" ); document.write( "\"P%28+z+%3C+a%29+=+0.5%2B0.1844+=+0.6844+\"\r
\n" ); document.write( "\n" ); document.write( "Look for \"0.6844\" under areas (in cumulative normal probability table) and read \"z\" backwards. \r
\n" ); document.write( "\n" ); document.write( "\"a=0.48\"
\n" ); document.write( "=>\"-a=-0.48\"\r
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