document.write( "Question 1131588: Sick-leave time used by employees of a firm in one month approximates a normal distribution with a mean of 165 hours and a variance of 225. In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of 0.992?\r
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document.write( "(Please round your answer to four decimal places if necessary. Thank you!)
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Algebra.Com's Answer #748675 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Probability of 0.992 is with a z-value of +2.41 \n" ); document.write( "mean is 165 \n" ); document.write( "sd is 15, sqrt(V) \n" ); document.write( "as question is written, want MORE than the value found. That means the amount of hours is at the z value of -2.41. \n" ); document.write( "z<=(x-mean)/sd \n" ); document.write( "-2.41=(x-165)/15 \n" ); document.write( "-36.15=x-165 \n" ); document.write( "x=128.85 hours \n" ); document.write( "That has a 99.2% probability of being exceeded. \n" ); document.write( " \n" ); document.write( " |