document.write( "Question 1131901: \"a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph. a passenger train left some time later traveling in the same direction at an average speed of 40 mph. after traveling for eight hours the passenger train caught up with the cattle train. find the number of the hours the cattle train traveled before the passenger train caught up\" \n" ); document.write( "

Algebra.Com's Answer #748643 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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\"a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph.
\n" ); document.write( " a passenger train left some time later traveling in the same direction at an average speed of 40 mph. after traveling for eight hours the passenger train caught up with the cattle train.
\n" ); document.write( " find the number of the hours the cattle train traveled before the passenger train caught up\"
\n" ); document.write( ":
\n" ); document.write( "let t = no. of hrs the cattle traveled when the passenger train caught up
\n" ); document.write( "When this happens, both trains will have traveled the same distance
\n" ); document.write( "Write distance equation (dist = speed * time)
\n" ); document.write( "32t = 40*8
\n" ); document.write( "32t = 320
\n" ); document.write( "t = 320/32
\n" ); document.write( "t = 10 hrs travel time of the cattle \n" ); document.write( "

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