document.write( "Question 1131901: \"a cattle train left washington and traveled toward Johannesburg at an average speed of 32 mph. a passenger train left some time later traveling in the same direction at an average speed of 40 mph. after traveling for eight hours the passenger train caught up with the cattle train. find the number of the hours the cattle train traveled before the passenger train caught up\" \n" ); document.write( "

Algebra.Com's Answer #748642 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+t%5B1%5D+\"$ = the time in hrs from the
\n" ); document.write( "time the cattle train left until the passenger
\n" ); document.write( "train departed
\n" ); document.write( " $\"+40%2A8+=+320+\"$ mi is the distance the passenger
\n" ); document.write( "train travels until it catches the cattle train
\n" ); document.write( "Start a stopwatch when the passenger train leaves
\n" ); document.write( "----------------------------------------------------------
\n" ); document.write( "Equation for the cattle train:
\n" ); document.write( " $\"+320+-+32t%5B1%5D+=+32%2A8+\"$
\n" ); document.write( " $\"+32t%5B1%5D+=+320+-+256+\"$
\n" ); document.write( " $\"32+t%5B1%5D+=+64+\"$
\n" ); document.write( " $\"+t%5B1%5D+=+2+\"$ hrs
\n" ); document.write( "----------------------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+320+-+64+=+256+\"$
\n" ); document.write( " $\"+256%2F32+=+8+\"$
\n" ); document.write( " $\"+320%2F%28+8+%2B+2+%29+=+32+\"$ mi/hr
\n" ); document.write( "OK\r
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