document.write( "Question 1131893: Heather has a total of $5000 to invest. She puts
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document.write( "part of it in an account paying 5%/year interest and the
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document.write( "rest in a GIC paying 7.2% interest. If she has $349 in
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document.write( "simple interest at the end of the year, how much was
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document.write( "invested at each rate?\r
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document.write( "what would the interest rate be at each percentage? Thank You! \n" );
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Algebra.Com's Answer #748620 by greenestamps(13195)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A setup for the traditional algebraic method of solving this kind of \"mixture\" problem.... \n" ); document.write( "Let x = amount invested at 5% \n" ); document.write( "Then (5000-x) = amount invested at 7.2% \n" ); document.write( "The total interest was $349: \n" ); document.write( " \n" ); document.write( "I'll leave it to you to solve the equation to find the answer; the decimals might make things a bit ugly. \n" ); document.write( "Here is a completely different way of solving this kind of problem -- much faster and easier than writing and solving an algebraic equation, if you understand the method and can do a little mental arithmetic. \n" ); document.write( "(1) $349 interest on a total investment of $5000 makes the overall interest rate . \n" ); document.write( " \n" ); document.write( "Comparing that interest rate to the individual rates of 5% and 7.2%, 6.98% is 9/10 of the way from 5% to 7.2%. (7.2-5 = 2.2; 6.98-5 = 1.98; 1.98/2.2 = 9/10). \n" ); document.write( "That means 9/10 of the total was invested at the higher rate. \n" ); document.write( "ANSWER: $4500 at 7.2%, $500 at 5%. \n" ); document.write( " |