document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102920>Question 102920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74856 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12X+9(100-X)=11.25*100<BR>\n" );
document.write( "12X+900-9X=1125<BR>\n" );
document.write( "3X=1125-900<BR>\n" );
document.write( "3X=225<BR>\n" );
document.write( "X=225/3<BR>\n" );
document.write( "X=75 POUNDS OF $12 COFFEE IS NEEDED.<BR>\n" );
document.write( "100-75=25 POUNDS OF $9 COFFEEE IS NEEDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "12*75+9*25=1125<BR>\n" );
document.write( "900+225=1125<BR>\n" );
document.write( "1125=1125\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );