document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131858>Question 1131858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of a line parallel to the line y= -2x + b and passes through the point (-1,-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748553 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> parallel lines have the same slope, so the slope of the line is -2<BR>\n" );
document.write( "point slope formula--y-y1=m(x-x1), m slope, (x1, y1) point<BR>\n" );
document.write( "y+3=-2(x+1)<BR>\n" );
document.write( "y=-2x-5<BR>\n" );
document.write( "graph of the line with the other line using b=+1, crossing y-axis at (0, 1)<BR>\n" );
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