document.write( "Question 1131853: Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and tge rest are quaters. What is the ratio of Alexander's nickles to dimes to quaters? \n" ); document.write( "
Algebra.Com's Answer #748543 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Alexander has 98 coins. Of the coins 2/7 are nickels, 3/7 are dimes, and the rest are quarters. What is the ratio of Alexander's nickles to dimes to quarters?----- \n" ); document.write( "------ \n" ); document.write( "Must be 1-(2/7+3/7) = 4/7 quarters \n" ); document.write( "----- \n" ); document.write( "Ratio:: 2:3:4 \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |