document.write( "Question 1131810: Use the normal curve to make the estimates requested. \r
\n" );
document.write( "\n" );
document.write( "The census from a certain year revealed that 22.8% of the U.S. veteran population were disabled. In a random selection of 100 veterans, estimate the probability that 30 to 40 of them were disabled. (Round your answer to three decimal places.) \n" );
document.write( "
Algebra.Com's Answer #748537 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! np=mean or 22.8 \n" ); document.write( "np(1-p) = variance or 22.8*0.772=17.60 \n" ); document.write( "sd= sqrt (V)=4.2 \n" ); document.write( "correction factor want mean between 29.5 and 40.5 \n" ); document.write( "z=(29.5-30)/4.2 or -0.12 \n" ); document.write( "z=(40.5-30)/4.2 or +2.5 \n" ); document.write( "probability z is between those values is 0.542 \n" ); document.write( " \n" ); document.write( " |