document.write( "Question 1131823: Help needed please.\r
\n" ); document.write( "\n" ); document.write( "The mean of a product is 15 days, with a standard deviation of 3 days. With normal distribution, what is the probability that measured shelf
\n" ); document.write( "life is more than 12 days?\r
\n" ); document.write( "\n" ); document.write( "I believe I am supposed to find the Z score, which I found to be -1, but not certain, and it doesn't seem right.\r
\n" ); document.write( "\n" ); document.write( "Can someone please guide me through how to figure this out?\r
\n" ); document.write( "\n" ); document.write( "Thanks!\r
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Algebra.Com's Answer #748502 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "You have the proper z score. Now use that value to find the area under the normal curve that is to the left of z = -1.00\r
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\n" ); document.write( "\n" ); document.write( "You can use a table such as this one (the back of your textbook should have something similar)
\n" ); document.write( "Locate the row that starts with -1.0 and the column that has 0.00 at the top. At the intersection of this row and column is the value 0.1587\r
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\n" ); document.write( "\n" ); document.write( "So, the area under the curve to the left of z = -1 is 0.1587 approximately
\n" ); document.write( "The area to the right of the z score is going to be roughly 1-0.1587 = 0.8413\r
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\n" ); document.write( "\n" ); document.write( "The approximate final answer is 0.8413 which is about a 84.13% chance
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