document.write( "Question 102926: The length of a rectangle is 2 in. more than twice its width. If the
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document.write( "perimeter of the rectangle is 34 in., find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #74849 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Let L represent the length and W represent the width. \n" ); document.write( ". \n" ); document.write( "You are told that L equals 2 inches more than 2W. In equation form this is: \n" ); document.write( ". \n" ); document.write( "L = 2W + 2 \n" ); document.write( ". \n" ); document.write( "Next you are told that the perimeter (P) is 34 inches. The perimeter is found by adding all \n" ); document.write( "the sides. In other words: \n" ); document.write( ". \n" ); document.write( "P = L + W + L + W \n" ); document.write( ". \n" ); document.write( "By combining like terms on the right side this can be simplified to: \n" ); document.write( ". \n" ); document.write( "P = 2L + 2W \n" ); document.write( ". \n" ); document.write( "Substitute 34 for the perimeter to get: \n" ); document.write( ". \n" ); document.write( "34 = 2L + 2W \n" ); document.write( ". \n" ); document.write( "But since L = 2W + 2 we can substitute 2W + 2 for L in the perimeter equation to get: \n" ); document.write( ". \n" ); document.write( "34 = 2(2W + 2) + 2W \n" ); document.write( ". \n" ); document.write( "Multiply out the right side by finding the product of 2 and each of the terms inside \n" ); document.write( "the parentheses. When you do, the equation becomes: \n" ); document.write( ". \n" ); document.write( "34 = 4W + 4 + 2W \n" ); document.write( ". \n" ); document.write( "Get rid of the 4 on the right side by subtracting 4 from both sides to get: \n" ); document.write( ". \n" ); document.write( "30 = 4W + 2W \n" ); document.write( ". \n" ); document.write( "Combine terms on the right side to reduce the equation to: \n" ); document.write( ". \n" ); document.write( "30 = 6W \n" ); document.write( ". \n" ); document.write( "Solve for W by dividing both sides by 6 to get: \n" ); document.write( ". \n" ); document.write( "5 = W \n" ); document.write( ". \n" ); document.write( "So we know the width is 5 inches. But our first equation tells us that the Length is \n" ); document.write( "twice the width plus 2 inches ... or 2 times 5 and then add 2. This makes the length 12 \n" ); document.write( "inches. \n" ); document.write( ". \n" ); document.write( "In summary, the width is 5 inches and the length is 12 inches. \n" ); document.write( ". \n" ); document.write( "Check by adding the 4 sides: 5 + 12 + 5 + 12 to get 34 inches for the perimeter, just as \n" ); document.write( "it should be. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and how to solve. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |