document.write( "Question 1131799: Stephanie and Jenny are selling wrapping paper for a school fundraiser. Customers can buy rolls
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document.write( "of plain wrapping paper and rolls of holiday wrapping paper. Stephanie sold 14 rolls of plain
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document.write( "wrapping paper and 9 rolls of holiday wrapping paper for a total of $446. Jenny sold 8 rolls of
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document.write( "plain wrapping paper and 3 rolls of holiday wrapping paper for a total of $212. Find the cost
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document.write( "each of one roll of plain wrapping paper and one roll of holiday wrapping paper. \n" );
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Algebra.Com's Answer #748486 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Stephanie: 14p + 9h = 446 (1) \n" ); document.write( "Jenny: 8p + 3h = 212 multiply all times -3 and add to equation (1) \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "14p + 9h = 446 \n" ); document.write( "-24p +-9h = -636 \n" ); document.write( "----------------- \n" ); document.write( "-10p + 0h = -190 \n" ); document.write( "-10p = -190 \n" ); document.write( "p = 19 the rolls of plain paper cost 19 each \n" ); document.write( "Now take one of the original equations, any one, and substitute for p to solve for h: \n" ); document.write( "14p + 9h = 446 \n" ); document.write( "14(19) + 9h = 446 \n" ); document.write( "266 + 9h = 446 \n" ); document.write( "h = 20 the rolls of holiday wrapping paper cost 20 each \n" ); document.write( "``````````````````````````````````````````````````````` \n" ); document.write( "Check: \n" ); document.write( "8p + 3h = 212 \n" ); document.write( "8(19) + 3(20) = 212 Correct, you now have the correct answers. \n" ); document.write( " |