document.write( "Question 1131799: Stephanie and Jenny are selling wrapping paper for a school fundraiser. Customers can buy rolls
\n" ); document.write( "of plain wrapping paper and rolls of holiday wrapping paper. Stephanie sold 14 rolls of plain
\n" ); document.write( "wrapping paper and 9 rolls of holiday wrapping paper for a total of $446. Jenny sold 8 rolls of
\n" ); document.write( "plain wrapping paper and 3 rolls of holiday wrapping paper for a total of $212. Find the cost
\n" ); document.write( "each of one roll of plain wrapping paper and one roll of holiday wrapping paper.
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Algebra.Com's Answer #748486 by addingup(3677)\"\" \"About 
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Stephanie: 14p + 9h = 446 (1)
\n" ); document.write( "Jenny: 8p + 3h = 212 multiply all times -3 and add to equation (1)
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\n" ); document.write( "14p + 9h = 446
\n" ); document.write( "-24p +-9h = -636
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\n" ); document.write( "-10p + 0h = -190
\n" ); document.write( "-10p = -190
\n" ); document.write( "p = 19 the rolls of plain paper cost 19 each
\n" ); document.write( "Now take one of the original equations, any one, and substitute for p to solve for h:
\n" ); document.write( "14p + 9h = 446
\n" ); document.write( "14(19) + 9h = 446
\n" ); document.write( "266 + 9h = 446
\n" ); document.write( "h = 20 the rolls of holiday wrapping paper cost 20 each
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\n" ); document.write( "Check:
\n" ); document.write( "8p + 3h = 212
\n" ); document.write( "8(19) + 3(20) = 212 Correct, you now have the correct answers.
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