document.write( "Question 1131776: In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2640 subjects randomly selected from an online group involved with ears. 1038 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys.\r
\n" );
document.write( "\n" );
document.write( "a) Find the best point estimate of the population proportion p.
\n" );
document.write( "= ____
\n" );
document.write( "(Round to three decimal places as needed.)\r
\n" );
document.write( "\n" );
document.write( "b) Identify the value of the margin of error E.
\n" );
document.write( "E = _____\r
\n" );
document.write( "\n" );
document.write( "(Round to three decimal places as needed.)\r
\n" );
document.write( "\n" );
document.write( "c) Construct the confidence interval.
\n" );
document.write( "= ____ < p < ____\r
\n" );
document.write( "\n" );
document.write( "(Round to three decimal places as needed.)\r
\n" );
document.write( "\n" );
document.write( "d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
\n" );
document.write( "A.
\n" );
document.write( "There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
\n" );
document.write( "B.
\n" );
document.write( "One has 90% confidence that the sample proportion is equal to the population proportion.
\n" );
document.write( "C.
\n" );
document.write( "One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
\n" );
document.write( "D.
\n" );
document.write( "90% of sample proportions will fall between the lower bound and the upper bound. \n" );
document.write( "
Algebra.Com's Answer #748470 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The point estimate is the best guess and that is 1038/2640 or 0.393 \n" ); document.write( "the half-interval is z(0.95), for two sided confidence interval, * sqrt (p*(1-p)/n); the sqrt term is the standard error of the mean. \n" ); document.write( "=1.645*sqrt(0.393*0.607/2640) \n" ); document.write( "=0.0156\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The CI is the point estimate+/- z*SE or 0.393+/-0.0156 \n" ); document.write( "(0.3774, 0.4086) \r \n" ); document.write( "\n" ); document.write( "This means that one is 90% confident that the true value, unknown and unknowable is in this interval. That is C. \n" ); document.write( "A is not true because the population proportion either does or doesn't fall in the interval, it isn't moving around. \n" ); document.write( "B is not usually true ever except in small populations. \n" ); document.write( "D refers to doing many sample proportions, and 90% of them will contain the population parameter. We don't know which 90 those are, however. \n" ); document.write( " |