document.write( "Question 1131775: Salaries of 43 college graduates who took a statistics course in college have a​ mean, x of $ 61,200. Assuming a standard​ deviation, sigma​, of ​$18,215​, construct a 90​% confidence interval for estimating the population mean mu.\r
\n" ); document.write( "\n" ); document.write( "Please help!
\n" ); document.write( "

Algebra.Com's Answer #748465 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
the half-interval width is z*sigma/sqrt(n)
\n" ); document.write( "z for 90% CI is 1.645
\n" ); document.write( "sigma is 18,215, and n is 43
\n" ); document.write( "half-interval is 4569.4, use 4569
\n" ); document.write( "interval is 61200+/-4569
\n" ); document.write( "($56631, $65769)
\n" ); document.write( "
\n" );