document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131761>Question 1131761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: &#8710;ABC –iso. &#8710;, m&#8736;BAC = 120° <BR>\n" );
document.write( "      <BR>\n" );
document.write( "AH<BR>\n" );
document.write( "  &#8869; <BR>\n" );
document.write( "BC<BR>\n" );
document.write( " , <BR>\n" );
document.write( "HD<BR>\n" );
document.write( " &#8869; <BR>\n" );
document.write( "AC<BR>\n" );
document.write( " <BR>\n" );
document.write( "       AD = a cm, HD = b cm<BR>\n" );
document.write( "       Find: P&#8710;ADH </SPAN>\n" );
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document.write( "The vertex angle BAC is 120 degrees; the angle bisector creates two angles of 60 degrees each.<br><BR>\n" );
document.write( "Since the triangle is isosceles, the angle bisector AH is perpendicular to side BC.<br><BR>\n" );
document.write( "Then triangle ADH is a 30-60-90 right triangle.<br><BR>\n" );
document.write( "Given AD = a and HD = b, with ADH a 30-60-90 right triangle, we know AH = 2a.  So the perimeter of triangle ADH is 2a+a+b = 3a+b. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );