document.write( "Question 1131759: ΔABC, m∠C = 90º
\n" ); document.write( " m∠B = 30º
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\n" ); document.write( "CM
\n" ); document.write( " - angle bisector
\n" ); document.write( " Find: m∠AMC
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Algebra.Com's Answer #748422 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "ΔABC, m∠ C = 90º
\n" ); document.write( " m∠B = 30º
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\n" ); document.write( "\n" ); document.write( "then,m∠ A = 60º\r
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\n" ); document.write( "CM- angle bisector, C = 90º id divided into two 45º angles MCA and MCB, and ΔABC into two Δ (ACM and BCM)\r
\n" ); document.write( "\n" ); document.write( "since ∠ $\"AMC+\"$ is in Δ $\"ACM\"$ , and we know two other angles, then\r
\n" ); document.write( "\n" ); document.write( " m∠ $\"AMC+=180-%2830%2B45%29=180-75=105\"$ º
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