document.write( "Question 102904: The length of a rectangular garden is 1 ft more than 2 times its width. If the perimeter of the garden is 44 ft, find both dimensions of the garden.\r
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Algebra.Com's Answer #74841 by jayanthihemkos@yahoo.com(87)\"\" \"About 
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The length of a rectangular garden is 1 ft more than 2 times its width. If the perimeter of the garden is 44 ft, find both dimensions of the garden.\r
\n" ); document.write( "\n" ); document.write( "Let the width of the garden w = x\r
\n" ); document.write( "\n" ); document.write( "The length of the garden l = 2x+1\r
\n" ); document.write( "\n" ); document.write( " peimeter of a rectangle = 2(l+w)\r
\n" ); document.write( "\n" ); document.write( " 2(l+w) = 44\r
\n" ); document.write( "\n" ); document.write( "2(x+2x+1) = 44\r
\n" ); document.write( "\n" ); document.write( "(x+2x+1) = 44/2\r
\n" ); document.write( "\n" ); document.write( "3x+1= 22\r
\n" ); document.write( "\n" ); document.write( "3x+1-1=22-1\r
\n" ); document.write( "\n" ); document.write( "3x = 21\r
\n" ); document.write( "\n" ); document.write( "3x/3= 21/3\r
\n" ); document.write( "\n" ); document.write( "x = 7ft\r
\n" ); document.write( "\n" ); document.write( "l = x = 7 ft\r
\n" ); document.write( "\n" ); document.write( "w = 2x+1\r
\n" ); document.write( "\n" ); document.write( "w = 2(7) +1\r
\n" ); document.write( "\n" ); document.write( "w = 15 ft\r
\n" ); document.write( "\n" ); document.write( "length = 7 ft and width = 15 ft is the solution\r
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