document.write( "Question 1131613: At present Allen is 10 years younger than Scott. Ten years from now, Scott’s age will be 3 times the present age of Allen. Find the present age of Allen and Scott. \n" ); document.write( "
Algebra.Com's Answer #748303 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Since the solution by @addingup is ABSOLUTELY WRONG, I came to bring the correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "A = S-10 (1)\r\n" ); document.write( "S+10 = 3A (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Substitute expression A = S-10 from eq(1) into eq(2), replacing A in equation (2).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "S + 10 = 3*(S-10)\r\n" ); document.write( "\r\n" ); document.write( "S + 10 = 3S - 30\r\n" ); document.write( "\r\n" ); document.write( "10 + 30 = 3S - S\r\n" ); document.write( "\r\n" ); document.write( "2S = 40 ====> S = 40/2 = 20.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. Scott is 20 years now. Allen is 20-10 = 10 years now.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check. Eq(1): A = S-10: 10 = 20-10 ! Correct !\r\n" ); document.write( "\r\n" ); document.write( " Eq(2): S+10 = 3A: 20+10 = 3*10 ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved and checked.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |