document.write( "Question 1131637: Find three consecutive integers such that the square of the smallest is 29 less than the product of the larger two. \n" ); document.write( "

Algebra.Com's Answer #748295 by ikleyn(52852) $\"\"$ $\"About$

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document.write( "n^2 = (n+1)*(n+2) - 29\r\n" );
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document.write( "n^2 = n^2 + n + 2n + 2 - 29\r\n" );
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document.write( "3n = 27  ====>  n = 9.\r\n" );
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document.write( "Answer.  9, 10 and 11.\r\n" );
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