document.write( "Question 1131620: the length of a rectangle is 7 cm less than three times its width. its area is 20 square centimeters. Please help me find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #748278 by MathLover1(20850)\"\" \"About 
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let the length be \"L\" and te width \"W\"\r
\n" ); document.write( "\n" ); document.write( "if the length of a rectangle is \"7cm\" \"less\" than \"three\"\"+times\" its \"width\", we have\r
\n" ); document.write( "\n" ); document.write( "\"L=3W-7\" ........eq.1\r
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\n" ); document.write( "\n" ); document.write( " if its area is \"20cm%5E2\", we have\r
\n" ); document.write( "\n" ); document.write( " \"L%2AW=20\"........substitute \"L\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"L%2AW=20\"\r
\n" ); document.write( "\n" ); document.write( "\"%283W-7%29%2AW=20\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-7W=20\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-7W-20=0\"........factor\r
\n" ); document.write( "\n" ); document.write( "\"3W%5E2-12W%2B5W-20=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%283W%5E2-12W%29%2B%285W-20%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"3W%28W-4%29%2B5%28W-4%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28W+-+4%29+%283+W+%2B+5%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28W+-+4%29++=+0\"=>\"W=4\"\r
\n" ); document.write( "\n" ); document.write( "if \"+%283+W+%2B+5%29+=+0\"=>\"3W=-5\"=>\"W=-5%2F3\"-> disregard negative solution for the width\r
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\n" ); document.write( "\n" ); document.write( "now find the length\r
\n" ); document.write( "\n" ); document.write( "\"L=3W-7\" ........eq.1
\n" ); document.write( "\"L=3%2A4-7\"
\n" ); document.write( "\"L=5\" \r
\n" ); document.write( "\n" ); document.write( "so, \"L=5cm\" and \"W=4cm\"\r
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