document.write( "Question 1131569: FIND EQUATION OF A PARABOLA WITH FOCAL WIDTH OF 8, AXIS PARALLEL TO Y AXIS, PASSING THROUGH (5,0) AND (9,-6. THANK YOU IN ADVANCE... \n" ); document.write( "
Algebra.Com's Answer #748262 by greenestamps(13334)\"\" \"About 
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\n" ); document.write( "If you use this form of the equation for a parabola

\n" ); document.write( "\"y+=+%281%2F%284p%29%29%28x-h%29%5E2%2Bk\"

\n" ); document.write( "Then the vertex is (h,k) and the focal width is 4p.

\n" ); document.write( "So with the two given points on the parabola, and knowing the focal width is 8, we get two equations in h and k:

\n" ); document.write( "(1) \"0+=+%281%2F8%29%285-h%29%5E2%2Bk\"
\n" ); document.write( "\"0+=+%281%2F8%29%28h%5E2-10h%2B25%29%2Bk\"

\n" ); document.write( "(2) \"6+=+%281%2F8%29%289-h%29%5E2%2Bk\"
\n" ); document.write( "\"6+=+%281%2F8%29%28h%5E2-18h%2B81%29%2Bk\"

\n" ); document.write( "Subtracting (1) from (2) eliminates k:

\n" ); document.write( "\"6+=+%281%2F8%29%28-8h%2B56%29\"
\n" ); document.write( "\"-8h%2B56+=+48\"
\n" ); document.write( "\"-8h+=+-8\"
\n" ); document.write( "\"h+=+1\"

\n" ); document.write( "Substituting h=1 in (1) gives us k:

\n" ); document.write( "\"0+=+%281%2F8%29%285-1%29%5E2%2Bk\"
\n" ); document.write( "\"0+=+2%2Bk\"
\n" ); document.write( "\"k+=+-2\"

\n" ); document.write( "ANSWER: An equation of the given parabola is \"y+=+%281%2F8%29%28x-1%29%5E2-2\"

\n" ); document.write( "A graph.... The vertex is (h,k) = (1,-2). p=2 is the distance from the vertex to the focus, so the focus is (1,0); so you can see in the graph that the focal width is 8, with the parabola having x-intercepts -3 and 5.

\n" ); document.write( "\"graph%28400%2C280%2C-10%2C10%2C-4%2C10%2C%281%2F8%29%28x-1%29%5E2-2%29\"
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