document.write( "Question 1131528: A rectangle is three times as long as it is wide. If the length is decreased by 2 cm and the width is increased by 3 cm, the new rectangle formed has an area of 42 cm2. What are the dimensions of the original rectangle? \n" ); document.write( "

Algebra.Com's Answer #748200 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "The dimensions of the rectangle are x and 3x.\r\n" );
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document.write( "Also, the problem says that\r\n" );
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document.write( "(3x-2)*(x+3) = 42.\r\n" );
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document.write( "2x^2 - 2x + 9x - 6 = 42\r\n" );
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document.write( "2x^2 + 7x - 48 = 0.\r\n" );
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document.write( "Solve the quadratic equation; take the positive root - it will be the width.\r\n" );
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document.write( "Then evaluate the length as 3x.\r\n" );
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