document.write( "Question 1131513: Two airplanes leave from an airport at the same time. One travels due south at a speed of
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Algebra.Com's Answer #748187 by greenestamps(13208)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Due south and due west are paths that are perpendicular to each other, so a triangle showing the planes' paths and the distance between the planes is a right angle.

\n" ); document.write( "Observe that the two speeds are 420 = 140*3 mph and 560 = 140*4 mph. So the right triangle is a scale model of the 3-4-5 right triangle; the distance between the planes is increasing at a rate of 140*5 = 700 mph.

\n" ); document.write( "The number of hours required for the distance between the planes to be 3150 miles is

\n" ); document.write( "\"3150%2F700+=+4.5\"

\n" ); document.write( "ANSWER: It will take 4.5 hours for the distance between the planes to be 3150 miles.
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