document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131509>Question 1131509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a right triangle is 42 and the sum of the squares of its sides is 722. Determine the area of the right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748179 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a right triangle is 42 and the sum of the squares of its sides is 722. Determine the area of the right triangle.<BR>\n" );
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document.write( "a + b + c = 42<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "a^2 + b^2 + c^2 = 722<BR>\n" );
document.write( "2c^2 = 722<BR>\n" );
document.write( "c = 19<BR>\n" );
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document.write( "a^2 + b^2 = 361<BR>\n" );
document.write( "a + b = 23<BR>\n" );
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document.write( "a^2 - 23a + 84 = 0<BR>\n" );
document.write( "a*b = 84<BR>\n" );
document.write( "Area = 42\r<BR>\n" );
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